The size of the sample should be obtained at 2401 in order to be 95% confident
Given that:
Margi of error, [tex]ME=0.02[/tex]
Population proportion, [tex]p=0.50[/tex]
To Find: The size of the sample that should be obtained in order to be 95% confident
Let the size of the sample be n
Using formula,
[tex]n=(p*(1-p))*(z(0.05/2)/ME)^{2} \\n=(0.5*(1-0.5))*(1.96/0.02)^{2} \\n=0.25*9604\\n=2401[/tex]
Therefore, the size of the sample should be obtained at 2401 in order to be 95% confident
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