Respuesta :
In a Base catalyst elimination, the base extracts a proton and the leaving group leaves simultaneously. In a Concentrated process, the leaving group leaves the base abstracts a proton.
Just as there are two mechanisms of substitution (SN2 and S N1), there are two
mechanisms of elimination (E2 and E1).
E2 mechanism — bimolecular elimination
E1 mechanism — unimolecular elimination
The E2 and E1 mechanisms differ in the timing of bond cleavage and bond formation, analogous to the SN2 and S N1 mechanisms.
E2 and S N2 reactions have some features in common, as do E1 and SN1 reactions.
Base removes a proton from the β-carbon atom,
while the halogen atom leaves from the α-carbon resulting in the formation of a π-bond. Such eliminations are also called β-eliminatione liminations are also called β elimination reactions
In a base-catalyzed elimination reaction, the base takes away a proton from the β position of the leaving group (the group that goes away with the bonding pair of electrons) and a double bond is formed. When the base is bulky it prefers to take away the proton from the less hindered position.
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