The ordered pair on the inequality y < 2/3x + 2 is D. (1,2)
How to determine the ordered pair?
The inequality is given as:
y < 2/3x + 2
Next, we test the options:
A. (0,3)
3 < 2/3 * 0 + 2
3 < 2 --- false
B. (-3,1)
1 < 2/3 * -3 + 2
1 < 0 --- false
C. (3,5)
5 < 2/3 * 3 + 2
5 < 4 --- false
D. (1,2)
2 < 2/3 * 1 + 2
2 < 2.67 --- true
Hence, the ordered pair on the inequality y < 2/3x + 2 is D. (1,2)
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