A dentist using a dental drill brings it from rest to maximum operating speed of 387,000 rpm in 2.4 s. Assume that the drill accelerates at a constant rate during this time. (a) What is the angular acceleration of the drill in rev/s2

Respuesta :

The angular acceleration of the drill is 2687.5 rev/s2

Given that operating speed of drill machine is 387000 rpm and the time given is 2.4s

We need to find the angular acceleration of the drill

Angular Acceleration is defined as the time rate of change of angular velocity.

The angular acceleration is also known as rotational acceleration.

It is a quantitative expression of the change in angular velocity per unit time.

The formula of angular acceleration is α =Δω/Δt

To find angular acceleration

α =Δω/Δt

Where Δω is the change in angular velocity

Δt is the change in time

Substituting the value  We get ,

  [tex]= \frac{387*10^3*1/60}{2.4}[/tex]

Therefore ,

α = 2687.5 rev/s2

Hence the angular acceleration is 2687.5 rev/s2

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