The answer is W = 1.06 MJ.
Now develop and express of Force required:
F = p*V*g
F = 1000*(2*0.5*x*8*dx)*g
F = 78480*x*dx
- Now, the work done is given by:
W = F.s
Where s is the distance from the top of the hose to the differential volume:
s = (5 - x)
We have the work as follows:
dW = 78400*x*(5-x)dx
Now integrate the following express from 0 to 3 till the tank is empty:
W = 78400*(2.5*x^2 - (1/3)*x^3)
W = 78400*(2.5*3^2 - (1/3)*3^3)
W = 78400*13.5 = 1058400 J
To find the weight of water, begin by way of finding the density(1 kg/L at 39.2°) and the extent of water. Convert the volume of water to liters after which multiply by way of the density to discover the burden.
Density is useful in calculating the load of materials which can be tough to weigh. you may decide its weight without a doubt with the aid of multiplying the density by using the dimensions, or quantity, of the item.
The unique weight, additionally called the unit weight, is the weight in keeping with the unit quantity of cloth. A typically used value is the precise weight of water in the world at 4 °C (39 °F), which is nine.807 kilonewtons consistent with cubic meters or 62. 43 pounds-force in keeping with cubic foot.
Learn more about the weight density of water here https://brainly.com/question/16794306
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