The linear function h(x) = 2x + 3, with the domain {-2, -1, 0, 1, 2}, has the range {-1, 1, 3, 5, 7}.
To find the range, we substitute each value of the domain for x, in the linear function h(x) = 2x + 3, as follows:
For the domain value, x = -2:
h(-2) = 2(-2) + 3,
or, h(-2) = -4 + 3,
or, h(-2) = -1.
Therefore, for the domain value, x = -2, the range value h(-2) is -1.
For the domain value, x = -1:
h(-1) = 2(-1) + 3,
or, h(-1) = -2 + 3,
or, h(-1) = 1.
Therefore, for the domain value, x = -1, the range value h(-1) is 1.
For the domain value, x = 0:
h(0) = 2(0) + 3,
or, h(0) = 0 + 3,
or, h(0) = 3.
Therefore, for the domain value, x = 0, the range value h(0) is 3.
For the domain value, x = 1:
h(1) = 2(1) + 3,
or, h(1) = 2 + 3,
or, h(1) = 5.
Therefore, for the domain value, x = 1, the range value h(1) is 5.
For the domain value, x = 2:
h(2) = 2(2) + 3,
or, h(2) = 4 + 3,
or, h(2) = 7.
Therefore, for the domain value, x = 2, the range value h(2) is 7.
Therefore, the linear function h(x) = 2x + 3, with the domain {-2, -1, 0, 1, 2}, has the range {-1, 1, 3, 5, 7}.
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