the nth term of another sequence is given by an bn 2 + the third term is 9 and the sixth term is 126. find the value of a and the value of b

Respuesta :

The values of a and b of the given sequence are; a = 6 and b = -15

How to find the Nth Term of a Sequence?

We are given the formula for nth term of a sequence as;

an² + bn

We are given that;

Third term = 9

Sixth term = 126

Thus;

a₃ = 9 = a(3)² + b(3)

9a + 3b = 9    ------(1)

Similarly for the 6th term;

a(6)² + b(6) = 126

36a + 6b = 126    ------(2)

Multiply eq 1 by 2 to get;

18a + 6b = 18    ------(3)

Subtract eq 3 from eq 2 to get;

18a = 108

a = 6

18(6) + 6b = 18

6b = 18 - 108

6b = -90

b = -90/6

b = -15

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