It will take 14.13 years for the disintegration rate of this sample to drop to 878 disintegrations per minute.
Given that,
Half life of Sr-90 = 28.49 years
This decay process is first order decay kinetics
So according to [tex]1^{st}[/tex] order reaction
Half life = 0.693/k
k= 0.693/28.49
k= 0.0243 [tex]years^{-1}[/tex]
According to the integrated rate law for [tex]1^{st}[/tex] order reaction
ln[Rn] = ln[Rn][tex]{o}[/tex] - kt …..(1)
where, Rn = 878 disintegrations/minute
Rn[tex]_{o}[/tex] = 1238 disintegrations/minute
Putting the values in equation (1)
ln[878] = ln[1238] - 0.0243 × t
6.7776 = 7.1212 - 0.0243 × t
0.0243t = 0.3436
t= 14.13 years
Hence, it will take 14.13 years for the disintegration rate of this sample to drop to 878 disintegrations per minute.
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