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A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three significant figures.

Respuesta :

The mass of a sample of tin whose temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy is 478.4g.

How to calculate mass?

The mass of a substance that underwent release of energy can be calculated using the following formula:

Q = mc∆T

Where;

  • Q = quantity of heat absorbed or released
  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

543 = m × 0.227 × 5

543 = 1.135m

m = 543/1.135

m = 478.4g

Therefore, the mass of a sample of tin whose temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy is 478.4g.

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