No, we cannot claim that the population mean breaking strength of the newly- manufactured cables is greater than pounds.
Given mean=1900, standard deviation=65, sample size=150, sample mean=1902, level of significance=0.01.
The hypothesis are:
[tex]H_{0}:\\[/tex]μ=1900
[tex]H_{1}:[/tex]μ>1900
We have to use z test as the sample size is large and we know the population standard deviation.
z=(x-μ)/σ/[tex]\sqrt{n}[/tex]
z=(1902-1900)/65/[tex]\sqrt{150}[/tex]
z=0.38
finding the p value:
p value=P(Z>z)
=P(Z>0.38)
=1-P(Z<0.38)
from the z table we get;
P(Z<0.38)=0.6480
Therefore p value=1-0.6480
=0.3520
If the p value is less than 0.01 then we reject the [tex]H_{0}[/tex] otherwise we will reject the null hypothesis.
In this problem we also reject the null hypothesis.
Hence we cannot claim that the population mean breaking strength of the newly- manufactured cables is greater than pounds.
Learn more about z test at https://brainly.com/question/14453510
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Question is incomplete. It should includes:
mean=1900,
standard deviation=65,
sample size=150,
sample mean=1902,
level of significance=0.01.
