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A particular industrial product is shipped in lots of 20. Testing to determine whether an item is defective is costly, and hence the manufacturer samples his production rather than using a 100 percent inspection plan. A sampling plan constructed to minimize the number of defectives shipped to customers calls for sampling five items from each lot and rejecting the lot if more than one defective is observed. (If rejected, each item in the lot is tested.) If a lot contains four defectives, what is the probability that it will be rejected

Respuesta :

The probability that the sample will be rejected if five items from 1 lot is selected is 26/15504.

Given Industrial product is product in lots of 20. If sample contains more than one defective then the lot will be rejected.

Probability is the chance of happening an event among all the events possible. The probability lies between 0 and 1. The formula of calculating probability is as under:

Probability= number of items/ total items.

Sample from 1 lot =5

Samples in 1 lot=20

Lot will be rejected when 1 sample, 2 sample , 3 sample, 4 sample or all the samples are defective.

Probability that the lot will be rejected=[tex](5C_{2} +5C_{3} +5C_{4} +5C_{5})/20C_{5}[/tex]

=(10+10+5+1)/15504

=26/15504

Hence the probability that lot will be rejected if the lot is rejected if more than one defective is observed is 26/15504.

Learn more about probability at https://brainly.com/question/24756209

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