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Multiply Conjugates Using the Product of Conjugates Pattern
In the following exercises, multiply each pair of conjugates using the Product of Conjugates Pattern
334. (9c − 2d)(9c + 2d)

Respuesta :

Answer:

The product is the difference of squares is [tex]$(9c-2d)(9c+2d)=81{{c}^2}-4{{d}^2}$[/tex]

Step-by-step explanation:

Explanation

  • The given expression is (9c-2d)(9c+2d).
  • We have to multiply the given expression.
  • Square the first term 9c. Square the last term 2d.

[tex]$\begin{aligned}&(9 c-2 d)(9 c+2 d)=(9 c)^{2}-(2 d)^{2} \\&(9 c-2 d)(9 c+2 d)=81 c^{2}-4 d^{2}\end{aligned}$[/tex]

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