Answer:
The product is the difference of squares is[tex]$\left(4-6y\right)\left(4+6y\right)=16-36{{y}^2}$[/tex]
Step-by-step explanation:
Explanation
[tex]$\begin{aligned}&(4-6 y)(4+6 y)=(4)^{2}-(6 y)^{2} \\&(4-6 y)(4+6 y)=16-36 y^{2}\end{aligned}$[/tex]