The solution for the system of equations: y = 3 - 2x and y = 8 - 7x, is x = 1, y = 1.
In the question, we are given a system of equations,
y = 3 -2x ... (i), and
y = 8 - 7x ... (ii).
We have been asked to solve the given system of equations.
To solve the system of equations, we do as follows:
Substitute the value of y = 3 - 2x, from (i) in (ii), to get:
y = 8 - 7x,
or, 3 - 2x = 8 - 7x, which is a linear equation in one variable.
To solve this, we follow these steps:
3 - 2x = 8 - 7x,
or, 3 - 2x + 7x = 8 - 7x + 7x {Adding 7x to both side of the equation},
or, 3 + 5x = 8 {Simplifying},
or, 3 + 5x - 3 = 8 - 3 {Subtracting 3 from both sides of the equation},
or, 5x = 5 {Simplifying},
or, 5x/5 = 5/5 {Dividing both sides of the equation by 5},
or, x = 1.
Substituting x = 1, in (i), we get:
y = 3 - 2x,
or, y = 3 - 2(1),
or, y = 3 - 2 = 1.
Thus, the solution for the system of equations: y = 3 - 2x and y = 8 - 7x, is x = 1, y = 1.
Note: The language seemed not gettable.
The question has been done assuming the question asking to solve the system of equations:
y = 3 - 2x, y = 8 - 7x.
Learn more about solving of system of equations at
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