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The swimming pool at Spring Valley High School is a rectangle with a width of 70 meters and a length of 30 meters. Around the perimeter of the pool is a tiled floor that extends w meters from the pool on all sides. Find an expression for the area of the tiled floor.

Respuesta :

adioabiola

The expression that can be used to find the area of the tiled floor is 4w² + 200w

Area of rectangle

  • Original rectangle:

Length = 70 Meters

Width = 30 meters

Area = length × width

= 70 × 30

= 2100

  • New rectangle(including tiled floor):

Length = 70 + 2w meters

Width = 30 + 2w meters

Area = length × width

= (70+2w) (30+2w)

= 2100 + 140w + 60w + 4w²

= 4w² + 200w + 2100

Area of the tiled floor = Area of new rectangle - area of old rectangle

= (4w² + 200w + 2100) - 2100

= 4w² + 200w + 2100 - 2100

= 4w² + 200w

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