When 5ml of 30% H2O2 is decomposed into water and oxygen, how many grams of oxygen and how many grams of water are left?

Respuesta :

The mas of the products are given below:

  • mass of oxygen produced = 0.7056 g of oxygen
  • mass of water produced = 0.794 g of hydrogen

How many moles are there in 5 ml of 30% of hydrogen peroxide?

The moles of hydrogen peroxide in 5 ml of 30% of hydrogen peroxide is calculated using the formula:

Moles = concentration * volume

Molarity of 30% of hydrogen peroxide = 8.82 mol/L

Moles = 8.82 * 5/1000 = 0.0441 moles

The equation of the the decomposition of hydrogen peroxide is given as:

2 H₂O₂ -----> 2 H₂O + O₂

Based on the mole ratio;

mass of oxygen produced = 0.0441/2 * 32 g = 0.7056 g of oxygen

mass of water produced = 0.0441 * 18 g = 0.794 g of hydrogen

Therefore, the mass of the products of the decomposition of hydrogen peroxide is determined from the mole ratio of the reaction.

Learn more about mole ratio at: https://brainly.com/question/19099163

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