A tub of water is emptied at a rate of 3 gallons per minute. The equation y –12 = –3(x – 1) models the amount of water remaining, where x is time (in minutes) and y is the amount of water left (in gallons). Analyze the work shown below to determine the initial amount of water.

1. Solve for the y-variable.

y – 12 = –3(x – 1)

y – 12 = –3x + 3

y = –3x +15

2. Write the equation using function notation.

f(x) = –3x +15

The tub started with
gallons of water.

Respuesta :

The initial amount of the water is 15 gallons

Linear functions

These are functions that has a leading degree of 1. Given the equation that represents the amount of water remaining after x minutes;

y - 12 = -3(x- 1)

y -12 = -3x + 3

y = -3x +3 + 12

y = -3x + 15

In order to determine the initial amount of water, we will substitute x =0 into the function

y = -3(0) + 15

y = 15

Hence the initial amount of the water is 15 gallons

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