The value of b that causes the system of equations to have infinite solutions is -6.
For that, we will try solving it first using the method of substitution in which we express one variable in another variable's form and then you can substitute this value in another equation to get a linear equation in one variable.
If there comes a = a situation for any a, then there are infinite solutions.
If there comes wrong equality, say for example, 3=2, then there are no solutions, else there is one unique solution to the given system of equations.
In the given problem, our equations are:
y = 6x + b
-3x + (1/2)^y = -3
So the value of b needs to be such that these two equations must be equal.
In the second equation:
[tex](1/2)^y = -3 + 3x\\y = -3^2 + 3x^2 \\y = -6 + 6x[/tex]
Then we must have:
6x - 6 = 6x + b
-6 = b
Thus, the value of b that causes the system to have infinite solutions is -6.
If you want to learn more about systems of equations;
brainly.com/question/13729904
#SPJ1