The tension in the cable is given by the newton's first law will be 163.622 N.
The summation of the force is equal to zero.
The formula is given as
ΣF = 0
Where m is the mass of the body and a is the acceleration.
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam.
Then the tension in the cable will be
Let T be the tension in the cable.
T sin 29° + T sin 53° – 210 = 0
On simplifying, we have
T (sin 29° + sin 53°) = 210
T = 163.622 N
More about the newton's first law link is given below.
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