Respuesta :
Answer:
g=9.64m/s^2.
Explanation:
Gravitational field strength (in other words, gravitational acceleration) is given as follows:g=GMR2g=R2GMwhere G=6.674×10−11m3kg⋅s2G=6.674×10−11kg⋅s2m3 is the gravitational constant, M=5.972×1024kgM=5.972×1024kg is the mass of the Earth, and R=6.371×106m+0.06×106m=6.431×106mR=6.371×106m+0.06×106m=6.431×106m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).
G = 9.4 m/s²
What is gravitational acceleration?
Gravitational acceleration (symbolized g) is an expression used in physics to indicate the intensity of a gravitational field.
It is expressed in meters per second squared (m/s²).
At the surface of the earth, 1 g is about 9.8 m/s 2 .
According to the question,
Gravitational field strength is given as follows:
[tex]g = \dfrac{GM}{R^2}[/tex]
Where[tex]G = 6.674\times 10^{-11}\dfrac{m^3}{kg\cdot s^2}[/tex] is the gravitational constant,
[tex]M = 5.972\times 10^{24}kg[/tex] is the mass of the Earth,
and [tex]R = 6.371\times 10^{6}m + 0.06\times 10^{6}m = 6.431\times 10^{6}m[/tex]
Here, m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).
Thus, obtain:
[tex]g = \dfrac{6.674\times 10^{-11}\cdot 5.972\times 10^{24}}{(6.431\times 10^{6})^2} \approx 9.64m/s^2[/tex]
g ≈9.64m/s 2
Therefore ,
The gravitational field strength is g = [tex]9.64m/s^2[/tex]
Learn more about gravitational field strength here:
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