The graph of the given quadratic equation is graph C.
How to sketch the quadratic equation?
Remember that for a quadratic equation with a vertex (h, k), the vertex form is given by:
[tex]y = a*(x - h)^2 + k[/tex]
Where a is the leading coefficient, in this case we have a = 1.
Here we have:
[tex]y = (x - 3)^2 - 25[/tex]
So the vertex is at (3, -25).
From that function we can also get the y-intercept, that is given by evaluating the function in x = 0, so we get:
[tex]y = (-3)^2 - 25 = -16[/tex]
So this function passes through (3, -25) and (0, -16). The sketch can be seen below.
Notice that from the given options only the third graph intercepts the y-axis on the negative region, so from that, we conclude that the third graph is the correct option.
If you want to learn more about quadratic equations:
https://brainly.com/question/1214333
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