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what is the solution to the system of equations below?
3x+y+2z=8
8y+6z=36
12y+2z=12

A. x=2, y=1, z=6
B. x=3, y=0, z=4
C. x=2, y=0, z=6
D. x=3, y=1, z=4

Respuesta :

The solution to the system of equation are x=2, y=0, z=6

System of equations

System of equations are equations that contains unknown variables.


Given the equations

3x+y+2z=8

8y+6z=36

12y+2z=12

From equation 2 and 3

8y+6z=36 * 1

12y+2z=12 * 3

______________

8y+6z=36

36y+6z= 36

Subtract

8y - 36y = 36 - 36

-28y =0

y = 0

Substitute y = 0 into equation 2

8(0)+6z=36

6z = 36

z = 6

From equation 1

3x+y+2z =8

3x + 0 + 2(6) = 8

3x = 8 - 12

3x = 6

x = 2

Hence the solution to the system of equation are x=2, y=0, z=6

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