Respuesta :
A straight line is represented by a linear equation given below.
The points are given as (1, 2) and (4, 4).
Start by calculating the slope (m)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
So, we have
[tex]m=\frac{4-2}{4-1} \\m=\frac{2}{3}[/tex]
What is the slope-intercept form of the line?
The equation in slope-intercept form is then calculated as:
[tex]y=m(x-x_1)+y_1[/tex]
So, we have:
[tex]y=\frac{2}{3}(x-1)+2\\ \\y=\frac{2}{3}(x-4)+4\\[/tex]
Expand
[tex]y=\frac{2}{3}(x-1)+2\\ y=\frac{2}{3} x-\frac{2}{3}+2[/tex]
Take LCM
[tex]y=2/3x+4/3[/tex]
Multiply through by 3
3y=2x+4
So, the possible equations are:
.[tex]3y=2x+4\\y=\frac{2}{3}x+\frac{4}{3} \\y=\frac{2}{3}(x-1)+2\\y=\frac{2}{3}(x-4)+{4}[/tex]
To learn more about linear equations visit:
brainly.com/question/11897796
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