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A football quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. He mates the receiver the first trew of the time When his fest throw is incomplete he misses the receiver on the second throw 10% of the tame What is the probability of not throwing me ball to a receiver on either throw?

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shubhamchouhanvrVT

The chance of not throwing the ball to a receiver on either throw is 0.0375, or 3.75 per cent.

What is probability?

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

This is event A when he misses the first throw. P(A) = 25%, or 0.25 Because event B takes place only after event A. When he misses on the second throw, event B occurs. P(B/A) = 15% or 0.15

P(A[tex]\cap[/tex]B) = P(A) P(B/A) P(A[tex]\cap[/tex]B)

P(A[tex]\cap[/tex]B) = (0.25)x(0.15) P(ANB)

P(A[tex]\cap[/tex]B) = 0.0375

Therefore the chance of not throwing the ball to a receiver on either throw is 0.0375, or 3.75 per cent.

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