The solution of the equation is x = -2±2i√2. The solution to the equation is found in the Sridharacharya formula.
A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
Given equation;
x² + 4x + 12 = 0
The solution to the equation is found as;
x² + 4x + 12 = 0
The solution to the equation is;
[tex]\rm x=-b \pm \frac{\sqrt{b^2-4ac}}{2a} \\\\ \rm x=-4 \pm \frac{\sqrt{4^2-4\times 4 \times 1}}{2\times 4} \\\\[/tex]
x = -2±2i√2
Hence the solution of the equation is x = -2±2i√2.
To learn more, about equations, refer;
https://brainly.com/question/10413253
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