The weight must be 288N placed on the end of the spring when it is 2m from the ground.
If an object is lifted, work is done against gravitational force. The object gains energy.
Given is a spring has a spring constant of 48 N/m. The end of the spring hangs 8 m above the ground. The final height of weight above the ground, h =2m
Using Hooke's law, expressed as
Force, F = k (x₂-x₁).
Put the values, we get
F = 48 (8-2)
F = 288 N
This force applied on the spring is equal to the weight placed on the spring.
Weight W= 288N.
Thus, the weight must be 288N.
Learn more about gravitational potential energy.
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