The centre of the circle is (1/2, 1) and the radius of the circle is 2 if the circle equation is x² + y² − x − 2y − 11/4 = 0
What is a circle?
It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)
The question is incomplete.
The complete question is:
A circle is defined by the equation given below.
x² + y² − x − 2y − 11/4 = 0
What are the coordinates for the centre of the circle and the length of the radius?
We know the standard form of a circle:
(x - h)² + (y - k)² = r²
Here (h, k) is the centre of the circle and r is the radius of the circle
[tex]\rm x^2 - x + \dfrac{1}{4} + y^2 - 2y + 1= \dfrac{11}{4} +\dfrac{1}{4} + 1\\\\[/tex]
[tex]\rm (x - \dfrac{1}{2})^2+(y-1)^2 = 2^2[/tex]
Thus, the centre of the circle is (1/2, 1) and the radius of the circle is 2 if the circle equation is x² + y² − x − 2y − 11/4 = 0
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