The simplified form of the expression has a numerator (x + 9)(2x + 1) and the denominator (x + 7) and the expression doesn't exist at (x = 9).
The given expression is:
= [(3x² - 27x)/(2x² + 13x - 7)]/(3x/4x² - 1)
Firstly, factorize the expression 4x² - 1.
4x² - 1 = (2x - 1)(2x + 1)
Then, factorize 2x² + 13x - 7.
2x² + 13x - 7 = 2x² + 14x - x - 7
2x(x + 7) - 1(x + 7)
= (2x - 1)(x + 7)
Then, factorize the equation 3x² - 27x.
3x² - 27x = 3x(x - 9)
The factorized terms will be substituted into the equation. This will be:
= [3x(x - 9)/(2x - 1)(x + 7)] / 3x[(2x - 1)(2x + 1)]
= (x + 9)(2x + 1)/(x + 7)
Learn more about quotient on:
brainly.com/question/673545
#SPJ1
