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: 2NaOH + H,S0A - Na,SO A + 2H,0 How many moles of sodium sulfate (Na,SO,) reproduced when 5.0 moles of sodium hydroxide (Na0H) are reacted with excess sulfuric acid? A 2.5 moles B 1.0 moles C 5.0 moles D 2.0 moles

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From the reaction, we can see that the number of moles produced is 2.5 moles of Na2SO4

What is a reaction?

Chemical reaction involves the combination between two or more species. In this case, the reaction  equation is; 2NaOH + H2S04 ----> Na2SO4 + 2H20.

Now we are told that sulfuric acid is in excess hence NaOH is the limiting reactant.

If 2 moles of NaOH produces 1 mole of Na2SO4

5 moles of NaOH produces 5 moles  * 1 mole/ 2 moles

= 2.5 moles of Na2SO4

Learn more about chemical reaction:https://brainly.com/question/22817140

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