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In an experiment to determine the latent heat of fusion of ice, 0.5 kg of ice at -5 °C was placed into 1.5 kg of water in a copper calorimeter of mass (including stirrer) of 0.2 kg with both water and calorimeter at 61 °C. The final temperature, when all the ice had melted, was 25.0 °C. Use the data to calculate the latent heat of fusion of ice. Mass of calorimeter = 0.20 kg. Mass of water = 1.50 kg. Mass of ice added = 0.50 kg. Start temperature of ice = -5.0 °C. Start temperature of water = 61 °C. Final temperature of water = 25.0 °C. Specific heat capacity of water = 4200 J/kg K. Specific heat capacity of ice = 2100 J/kg K. Specific heat capacity of copper = 420 J/kg K.​

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onyebuchinnaji

The latent heat of fusion of the ice used in the experiment is determined as 396,648 J/kg.

Latent heat of fusion of ice

The latent heat of fusion of the ice is calculated as follows;

Heat lost by water and calorimeter = heat gained by the ice

mcΔθ + mcΔθ = mLf + mcΔθ₁ + mcΔθ₂

(1.5)(4200)(61 - 25) + 0.2(420)(61 - 25) = 0.5Lf + 0.5(2100)(0 - -5) + 0.5(2100)(25 - 0)

(1.5)(4200)(36) + 0.2(420)(36) = 0.5Lf + 0.5(2100)(5) + 0.5(2100)(25)

229,824 = 0.5Lf + 31,500

0.5Lf = 198,324

Lf = 198,324/0.5

Lf = 396,648 J/kg

Thus, the latent heat of fusion of the ice used in the experiment is determined as 396,648 J/kg.

Learn more about heat fusion here: https://brainly.com/question/87248

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