27. The energy , in electronvolts, of an emitted photon when an electron transition from n=3 to n = 2 is -1.89 eV.
28. The energy of this emitted photon in joules is -3.0278 x 10⁻¹⁹ Joules.
29. The frequency of the emitted photon is 4.572 x 10¹⁴ Hz.
30. The color of light associated with this photon is Red.
It is the number of oscillations per second of the sinusoidal wave.
Given is the Great Nebula in the constellation Orion consists primarily of excited hydrogen gas.
The electrons in the atoms of excited hydrogen have been raised to higher energy levels. When these atoms release energy, a frequent electron transition is from the excited n = 3 energy level to the n = 2 energy level, which gives the nebula one of its characteristic colors.
27. The energy of transition between n = 3 to n = 2 is
E = R h e (1/n₁² - 1/n₂²)
where R = Rydberg constant and h = Planck's constant.
Substitute the values, we get
E = 1.0974 x 10⁻⁷ x 6.626 x 10⁻³⁴ x 1.6 x 10⁻¹⁹ (1/3² - 1 /2²)
E = -1.89 eV
28. Energy in joules can be obtained by multiplying 1.6 x 10⁻¹⁹ . So we have
E = -1.89 eV x 1.6 x 10⁻¹⁹ J/eV
E = -3.0278 x 10⁻¹⁹ Joules
29. Wavelength associated with the photon emitted is
1/λ = R (1/n₂² - 1/n₁² )
Substitute the values, we get
1/ λ = 1.524 x 10⁶ /m
The frequency is related to the wavelength as
f = c/λ where c = speed of light
f = 3 x 10⁸ x 1.524 x 10⁶
f = 4.572 x 10¹⁴ Hz
30. The color of light associated with the photon of calculated frequency is Red.
Learn more about frequency.
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