The charge on the ball developed will be 1.78 x 10⁻⁷ Coulomb.
The field developed when a charge is moved. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of charge,
Given is an electric field E = 100,000i N/C causes the 5.0 g point charge to hang at a 20° angle.
If T is the tension and θ is the angle, then
The force in x direction Fx = T sinθ
Force in y direction Fy = T cosθ = mg
Dividing both the equation, we have
tan θ = qE /mg
Substitute the given values in the question, we have
q = 5 x10⁻³ x 9.81 x tan 20 /100000
q = 1.78 x 10⁻⁷ Coulomb.
Thus, the charge of ball is 1.78 x 10⁻⁷ Coulomb.
Learn more about electric field.
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