4 | x + 6 | = 16
Divide both sides by 4.
[tex]\bf{\dfrac{4|x+6|}{4}=\dfrac{16}{4} }[/tex]
[tex]\bf{|x+6|=4 }[/tex]
Absolute value is solved.
[tex]\bf{|x+6|=4 }[/tex]
We know either x + 6 = 4 or x + 6 = -4.
x + 6 = 4 (Possibility 1)
x + 6 - 6 = 4 - 6 (Subtract 6 from both sides)
x=−2
x + 6 = -4 (Possibility 2)
x + 6 - 6 = -4 - 6 (Subtract 6 from both sides)
x=-10
Solution:
x=−2 or x=−10
[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
