The fundamental frequency (in hertz) of a piano string is directly proportional to the square root of its tension and inversely proportional to its length and the square root of its mass density. A string has a frequency of 400 hertz. Find the frequency of a string with each property

(a) four times the tension
hz

(b) twice the length
hz

(c) four times the tension and twice the length
hz

Respuesta :

The frequency of a string with each property respectively is 800 Hz, 200 Hz and 400 Hz.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let f represent the frequency, l represent the length, T represent the tension and m represent the mass density.

The fundamental frequency (in hertz) of a piano string is directly proportional to the square root of its tension and inversely proportional to its length and the square root of its mass density.

Hence:

f = k[√T / (l * √m)]

f = 400, hence:

400 = k[√T / (l * √m)]

k = 400[(l * √m) / √T]

a) For four times the tension:

f = 400[(l * √m) / √T] * [√(4T) / (l * √m)] = 400 * 2 = 800 Hz

b) Twice the length

f = 400[(l * √m) / √T] * [√(T) / (2l * √m)] = 400 / 2 = 200 Hz

a) For four times and twice the length:

f = 400[(l * √m) / √T] * [√(4T) / (2l * √m)] = 400 * 2 / 2 = 400 Hz

The frequency of a string with each property respectively is 800 Hz, 200 Hz and 400 Hz.

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