The volume of 1.6 M NaHCO₃ must be poured on the spill to react completely with the sulfuric acid is 323.75 milliliters
Molarity (M) is the amount of a substance in a certain volume of solution.
Molarity is defined as the moles of a solute per liters of a solution.
Molarity is also known as the molar concentration of a solution.
Let's find out the number of moles of H₂SO₄ in 81 ml of 3.2 M H₂SO₄
Number of Moles = Volume (ltr) X Molarity
= 0.081 x 3.2 = 0.259 mol H₂SO₄
According to the question given, balanced chemical equation ;
H₂SO₄+ 2NaHCO₃ --> Na₂SO₄ + 2CO₂ + 2H₂O
From the balanced equation -
1 mol H₂SO₄ reacts with 2 mol of NaHCO₃
Therefore,
0.259 mol H₂SO₄ reacts with X mol of NaHCO₃
X = 0.259 x 2 mol = 0.518 moles of NaHCO₃
we know,
Number of mole = Volume x Molarity
For NaHCO₃ ;
0.518 = V x 1.6
V = 0.323 ltr
V = 323.75 mL NaHCO₃
Hence, 323.75 milliliters of 1.6 M NaHCO₃ must be poured on the spill to react completely with the sulfuric acid.
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