The maximum height reached by the ball thrown by the boy is determined as 12.5 m.
The angle of projection of the ball is calculated as follows;
R = u²sin2θ/g
50 = u²/9.8
u² = 50 x 9.8
u² = 490
u = 22.14 m/s
H = u²sin²θ/2g
H = (22.14² x (sin45)²)/(2 x 9.8)
H = 12.5 m
Thus, the maximum height reached by the ball thrown by the boy is determined as 12.5 m.
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