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A seesaw is a total of 10 meters long with a fulcrum in the middle. If a 50 kg student sits on it 3 meters from the fulcrum, what distance on the other side must a 75 kg student sit to balance the seesaw

Respuesta :

The distance on the other side must a 75 kg student sit to balance the seesaw is 6.33 m.

Distance of 75kg student

The distance on the other side must a 75 kg student sit to balance the seesaw is calculated as follows;

50(5 - 3) = 75x

50 x 2 = 75x

100 = 75x

x = 100/75

x = 1.33 m

distance from other side = 5 + 1.33 m = 6.33 m

Thus, the distance on the other side must a 75 kg student sit to balance the seesaw is 6.33 m.

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