Given function
[tex]\\ \rm\Rrightarrow h(x)=\begin{cases}\sf \dfrac{1}{4}x-4,x\leqslant 0\\ \sf\dfrac{1}{3}x-3,0< x\leqslant 3\\ \sf \dfrac{1}{2}x-2,x\geqslant 4\end{cases}[/tex]
Take first one and put 0
[tex]\\ \rm\Rrightarrow h(0)[/tex]
[tex]\\ \rm\Rrightarrow {0-4}[/tex]
[tex]\\ \rm\Rrightarrow -4[/tex]
The graph must contain (0,-4)
Only graph B contains (0,-4). so
