Using the arrangements formula, it is found that you can make 12 different 4 digit combinations with the numbers 1, 4, 8 and 8.
What is the arrangements formula?
The number of possible arrangements of n elements is given by the factorial of n, that is:
[tex]A_n = n![/tex]
When there are repeating elements, repeating [tex]n_1, n_2, \cdots, n_n[/tex] times, the number of arrangements is given by:
[tex]A_n^{n_1, n_2, \cdots n_n} = \frac{n!}{n_1!n_2! \cdots n_n!}[/tex]
In this problem, there are 4 digits, one of which repeats twice, hence the number of arrangements is given by:
[tex]A_{4}^{2} = \frac{4!}{2!} = 12[/tex]
More can be learned about the arrangements formula at https://brainly.com/question/25925367
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