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A bicycle is traveling north at 5.0 m/s. the mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radius of 20 cm. what are the magnitude and direction of the angular momentum of the wheel about its axle? \) 2.0 kgm2/ towarde ¡he west b) 5.0 kg m2/s vertically upwards c) 2.0 kg m2/s towards the east d) 5.0 kg-m2/s towards the cast e) 5.0 kg m2/s towards the west (wii,12)

Respuesta :

Answer:

H(angular momentum) = I * ω       inertia * angular speed

ω = V / R = 5 m/s / .2 m = 25 / s

I = M R^2 = 2 kg * (.2 m)^2 = .08 kg-m^2

H = 25 / s * .08 kg-m^2 = 2 kg-m^2/s

Using the right hand rule - the angular momentum is towards the west - the same direction as the angular velocity

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