If we take the expression x = (5.2 × 10³ M⁻² s⁻¹) (0.39 M)³ and solve for x, we get x = 2.0 × 10³ M s⁻¹, being M = molar and s = seconds.
Molarity (M) is a unit of concentration equivalent to moles of solute per liter of solution.
Let's consider the following expression for x, where M is molar and s is seconds.
x = (5.2 × 10³ M⁻² s⁻¹) (0.39 M)³
We will solve it for x using properties of powers.
[tex]x = (\frac{5.2 \times 10^{3} }{M^{2}s })(0.39)^{3} (M)^{3} = 2.0 \times 10^{3} M s^{-1}[/tex]
If we take the expression x = (5.2 × 10³ M⁻² s⁻¹) (0.39 M)³ and solve for x, we get x = 2.0 × 10³ M s⁻¹, being M = molar and s = seconds.
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