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A cylinder-piston system contains an ideal gas at a pressure of 1.5 105 pa.
the piston is pushed out, allowing the gas to expand from an initial volume of
0.0002 m2 to a final volume of 0.0006 m3. the system absorbs 32 j of heat
during this process. what is the change in internal energy? [use au=q-w=q-
pav]

Respuesta :

onyebuchinnaji

The change in the internal energy of the ideal gas is determined as -28 J.

Work done on the gas

The work done on the ideal gas is calculated as follows;

w = -PΔV

w = -1.5 x 10⁵(0.0006 - 0.0002)

w = -60 J

Change in the internal energy of the gas

ΔU = w + q

ΔU = -60J + 32 J

ΔU = -28 J

Thus, the change in the internal energy of the ideal gas is determined as -28 J.

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