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two points a(2 "-4)" and b (-6 4) are given. p is the midpoint of l the line segment AB. Find the equation of the straight line with the slope of 3 passing through P

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Medunno13

Answer: y=3x+6

Step-by-step explanation:

[tex]\text{mdpt}_{\overline{AB}}=\left(\frac{2-6}{2}, \frac{-4-4}{2} \right)=(-2, 0)[/tex]

So, the equation of the line is:

[tex]y=3(x+2)\\y=\boxed{3x+6}[/tex]

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