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Ampère placed two 1.50-m wires parallel to each other so that they were 4.80 cm apart.
He delivered a current of 6.50 A to the wires. Both wires experienced an external
magnetic field of 2.71 X 10^−5 T. Determine the force on one of the wires.

Respuesta :

The forces on one of the wires will be 0.000264 N.It is the field sensed around a moving electric charge that gives rise to the magnetic force.

What is a magnetic field?

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem is;

I is the current = 6.50 A

B is the magnetic field=f 2.71 X 10⁻⁵ T

The force on the wire is;

[tex]\rm F= BIL \\\\\ F=2.71 \times 10^{-5} \ T \times 6.50 \ A \times 1.50 \ m \\\\\ F=0.000264225 \ N[/tex]

Hence, the force on one of the wires will be 0.000264 N.

To learn more about the magnetic field refer to the link;

https://brainly.com/question/19542022

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