The probability of getting two red lenses when two are selected will be 2/13.
The probability of favorable events to the total number of occurrences.
A box contains four red, three blue, and six green lenses.
Two lenses are randomly selected from the box.
Then the probability of getting two red lenses when two are selected if the first selection is not replaced before the second selection is made will be
The total number of the event will be
Total event = ¹³C₂
Total event = 78
Then the favorable event will be
Favorable event = ⁴C₁ x ³C₁
Favorable event = 4 x 3 = 12
Then we have
P = 12 / 78
P = 2/13
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