The length of a rectangular poster is 7 more inches than three times its width. The area of the poster is 26 square inches. Solve for the dimensions (length and width) of the poster.

Respuesta :

The length and the width of the rectangle are 2 inches and 13 inches respectively.

What is a rectangle?

A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but the reverse statement may or may not be true.

Let the width of the rectangle be represented by x.

Given the length of a rectangular poster is 7 more inches than three times its width. Therefore, the length can be written as,

Length = (3 × width)+7 more inches = 3x+7

Also, given the area of the poster is 26 sq. inches, therefore, the area of will be,

26 = x × (3x+7)

26 = 3x² + 7x

3x² + 7x - 26 = 0

[tex]x = \dfrac{-(7)\pm\sqrt{(7)^2-4(3)(-26)}}{2(3)}\\\\x = 2, -4.333[/tex]

Since the width can not be negative, therefore, the width of the rectangle is 2. The dimensions of the rectangle are,

Width = x = 2 inches

Length = 3x + 7 = 13 inches

Hence, the length and the width of the rectangle are 2 inches and 13 inches respectively.

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