The points that are 4 units apart are B and D
Which points are 4 units apart? On a coordinate plane, point A is at (-2, 4), point B is at (3, -6), point C is at (-1, 0), point D is at (3, -2).
B and C
C and D
A and C
B and D
To do this, we simply calculate the distance using the following equation
[tex]d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2[/tex]
Using the given points, we have:
[tex]BC = \sqrt{(3+ 1)^2 + (-6 -0)^2} = 7.2[/tex]
[tex]CD = \sqrt{(-1 - 3)^2 + (0 +2)^2} = 4.5[/tex]
[tex]AC = \sqrt{(-2 + 1)^2 + (4 -0)^2} = 4.1[/tex]
[tex]BD = \sqrt{(3 - 3)^2 + (-6 +2)^2} = 4[/tex]
Hence, the points that are 4 units apart are B and D
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