The wavelength of the 5th harmonic will be 145 cm. None of the given options are correct.
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The length of the string corresponds to one-half of a wavelength for the first harmonic.
[tex]\rm \lambda_1= \frac{1}{2} L \\\\ \lambda_5=5 \times \frac{1}{2} L \\\\\ \lambda_5=5 \times \frac{1}{2} \times 58 \ cm \\\\\ \lambda_5 = 145 \ cm[/tex]
Hence the wavelength of the 5th harmonic will be 145 cm.
To learn more about the wavelength refer to the link;
https://brainly.com/question/13533093
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