The equation of the line that has a slope of -4 and goes through (-1,6) is y- 6 = -4(x+1)
Equation of a line in point-slope form
The equation of a line in point-slope form is expressed as:
y i y1 = m(x-x1)
where;
m is the slope
(x1, y1) is any point on the line
Given the following
Slope = -4
point = (-1, 6)
Substitute
y - 6 = -4(x-(-1))
y- 6 = -4(x+1)
Hence the equation of the line that has a slope of -4 and goes through (-1,6) is y- 6 = -4(x+1)
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