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8. The straight line depreciation equation for a car is
y = -2,680x + 26,800.
a. How much is the car worth afte-months?
b. How much is the car worth after 75 months?
c. Suppose that M represents the length of time in months when
the car still has value. Write an algebraic expression to represent
the value of this car after M months.
The graph of
O

Respuesta :

An algebraic expression to represent the value of this car after M months is y=Mx+C.

We have given that the

The straight-line depreciation equation for a car is,

y = -2,680x + 26,800.

therefore after 4moths

y = -2,680(4) + 26,800.

y = -10720 + 26,800.

y=16080

What is the slope?

The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as rise over run (change in y divided by change in x)

b. For find after the 75 months replace x by 75 and slolve the given inequality.

Suppose that M represents the length of time in months when

the car still has value.

An algebraic expression to represent the value of this car after M months.

y=Mx+C.

To learn more about the line visit:

https://brainly.com/question/1821791

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